VS200

[iamskippy]

Imo this reel will handle foot balls no problem, its a preference. And if you wanna know the line capacity do the math you know the diamater of braid a, mulitply braid a x total yards then divide the diameter of braid b, and thus you have your total line for that poundage. Basic algebra
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[Pete_G]

It depends on what you consider a football.

This fish was caught on a VS200. 180 pounds. No fancy Japanese jigging rod, just an old 7 foot Calstar. It is the upper end of the spectrum though, and fish fighting skills and boat handling contributed greatly to the catch as well as how quickly it was in the boat. I forget what the reel holds for 65# test, but it's enough unless you hook something REALLY hot, don't have the drag set properly, or refuse to chase a fish. Attach the braid to the hub, no backing.

If I had a choice of Van Staals hands down I'd take a VS275 for the faster retrieve and additional capacity, it's just better weapon for the task at hand but if a 200 is what you already own I wouldn't think twice about taking it into battle. I used one for many years until I got a 275.

[big jay]

Originally Posted by Pete_G

It depends on what you consider a football.

This fish was caught on a VS200. 180 pounds. No fancy Japanese jigging rod, just an old 7 foot Calstar. It is the upper end of the spectrum though, and fish fighting skills and boat handling contributed greatly to the catch as well as how quickly it was in the boat. I forget what the reel holds for 65# test, but it's enough unless you hook something REALLY hot, don't have the drag set properly, or refuse to chase a fish. Attach the braid to the hub, no backing.

If I had a choice of Van Staals hands down I'd take a VS275 for the faster retrieve and additional capacity, it's just better weapon for the task at hand but if a 200 is what you already own I wouldn't think twice about taking it into battle. I used one for many years until I got a 275.

That was a fun day.

[Redsoxticket]

Better yet,
divide the know total yds of braid A by know diameter of braid A then multiply by the diameter of braid B, the result is the total line for braid B.

Byds = (Ayds/Adia) x Bdia

Advanced algebra
Posted from my iPhone/Mobile device[/QUOTE]

Originally Posted by iamskippy

Imo this reel will handle foot balls no problem, its a preference. And if you wanna know the line capacity do the math you know the diamater of braid a, mulitply braid a x total yards then divide the diameter of braid b, and thus you have your total line for that poundage. Basic algebra
Posted from my iPhone/Mobile device

Posted from my iPhone/Mobile device

[iamskippy]

Originally Posted by Redsoxticket

Advanced algebra

for some lol

[Bill L]

I don't know, the cross sectional area of the braid, which will make up the volume on the spool, is not directly proportional to the diameter (a=pi*d^2/4), so this approach could be flawed

[PRBuzz]

Originally Posted by Bill L

I don't know, the cross sectional area of the braid, which will make up the volume on the spool, is not directly proportional to the diameter (a=pi*d^2/4), so this approach could be flawed

So now you are getting into that "new math" arena and the answer is the reel will take braid from spool A and load it onto spool B (found in the reel) when a force is applied to the reel handle to produce a centripetal force. Stop applied force when either spool A is empty or spool B is full.....

[Redsoxticket]

Originally Posted by Redsoxticket

Better yet,
divide the know total yds of braid A by know diameter of braid A then multiply by the diameter of braid B, the result is the total line for braid B.

Byds = (Ayds/Adia) x Bdia

Advanced algebra
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Oops forgetaboutit, your going to need a bigger spool, iamskippy will get you much closer but not accurate as indicated by BillL

How about the volume of the spool converted in cubic ft divided by the volume of "one foot length of braid converted in cubic feet" The result would be the number of one foot strands to fill the volume of spool.
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